-20x^2+33x+14=0

Solution for -20x^2+33x+14=0 equation:

-20x^2+33x+14=0

a = -20; b = 33; c = +14;
Δ = b2-4ac
Δ = 332-4·(-20)·14
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-47}{2*-20}=\frac{-80}{-40}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+47}{2*-20}=\frac{14}{-40}
=-7/20
$